leetcode 222: Count Complete Tree Nodes

Count Complete Tree Nodes

Total Accepted: 93 Total Submissions: 678

Given a complete binary tree, count the number of nodes.

Definition of a complete binary tree from Wikipedia:
In a complete binary tree every level, except possibly the last, is completely filled, and all nodes in the last level are as far left as possible. It can have between 1 and 2^h nodes inclusive at the last level h.

[思路]

用暴力法, recursive求会超时 O(N).   如果从某节点一直向左的高度 = 一直向右的高度, 那么以该节点为root的子树一定是complete binary tree. 而 complete binary tree的节点数,可以用公式算出 2^h - 1. 如果高度不相等, 则递归调用 return countNode(left) + countNode(right) + 1.  复杂度为O(h^2)  

[CODE]

/** * Definition for a binary tree node. * public class TreeNode { *     int val; *     TreeNode left; *     TreeNode right; *     TreeNode(int x) { val = x; } * } */public class Solution {    public int countNodes(TreeNode root) {        if(root==null) return 0;                int l = getLeft(root) + 1;        int r = getRight(root) + 1;                if(l==r) {            return (2<<(l-1)) - 1;        } else {            return countNodes(root.left) + countNodes(root.right) + 1;        }    }        private int getLeft(TreeNode root) {        int count = 0;        while(root.left!=null) {            root = root.left;            ++count;        }        return count;    }        private int getRight(TreeNode root) {        int count = 0;        while(root.right!=null) {            root = root.right;            ++count;        }        return count;    }}