HDU 1021 Fibonacci Again

来源:互联网 发布:冥界三巨头 知乎 编辑:程序博客网 时间:2024/04/29 06:23

Description

There are another kind of Fibonacci numbers: F(0) = 7, F(1) = 11, F(n) = F(n-1) + F(n-2) (n>=2). 
 

Input

Input consists of a sequence of lines, each containing an integer n. (n < 1,000,000). 
 

Output

Print the word "yes" if 3 divide evenly into F(n). 

Print the word "no" if not. 
 

Sample Input

012345
 

Sample Output

nonoyesnonono

公式: (a+b)%k = (a%k + b%k)%k

    (a-b)%k = (a%k - b%k)%k


#include <stdio.h>int main() {int n;while (scanf("%d", &n) == 1) {if (n == 1 || n == 0) {printf("no\n");continue;}if ((n - 2) % 4 == 0)printf("yes\n");elseprintf("no\n");}return 0;}




0 0
原创粉丝点击