HDU 1021 Fibonacci Again
来源:互联网 发布:冥界三巨头 知乎 编辑:程序博客网 时间:2024/04/29 06:23
Description
There are another kind of Fibonacci numbers: F(0) = 7, F(1) = 11, F(n) = F(n-1) + F(n-2) (n>=2).
Input
Input consists of a sequence of lines, each containing an integer n. (n < 1,000,000).
Output
Print the word "yes" if 3 divide evenly into F(n).
Print the word "no" if not.
Print the word "no" if not.
Sample Input
012345
Sample Output
nonoyesnonono
公式: (a+b)%k = (a%k + b%k)%k
(a-b)%k = (a%k - b%k)%k
#include <stdio.h>int main() {int n;while (scanf("%d", &n) == 1) {if (n == 1 || n == 0) {printf("no\n");continue;}if ((n - 2) % 4 == 0)printf("yes\n");elseprintf("no\n");}return 0;}
0 0
- HDU 1021 Fibonacci Again
- HDU 1021 Fibonacci Again
- HDU 1021 Fibonacci Again
- hdu 1021 Fibonacci Again
- hdu 1021 Fibonacci Again
- HDU 1021 Fibonacci Again
- HDU 1021 Fibonacci Again
- Hdu 1021 - Fibonacci Again
- hdu 1021 Fibonacci Again
- hdu 1021 Fibonacci Again
- hdu 1021 Fibonacci Again
- hdu 1021 Fibonacci Again
- HDU 1021 Fibonacci Again
- hdu 1021 - Fibonacci Again
- hdu 1021Fibonacci Again
- hdu 1021-Fibonacci Again
- hdu-1021-Fibonacci Again
- hdu 1021 Fibonacci Again
- spring mvc配置文件
- java基础从零开始
- 2015.7.30
- Linux Tcp客户端和服务器端代码实现
- 机试算法讲解: 第10题 让我们来查询学生的信息
- HDU 1021 Fibonacci Again
- 黑马程序员-关于IO的学习
- java并发的延时任务和周期任务
- 【西祠日志】【12】逐步有成效,asp留言板即将再次完成
- android开发环境异常处理
- Unity3D:粒子系统Particle System
- 常用的linux配置和软件备忘录
- Mysql 主键自增长问题小结
- RFC 3031 Multiprotocol Label Switching Architecture 学习笔记一