南邮 OJ 1086 A + B Problem (3)

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A + B Problem (3)

时间限制(普通/Java) : 1000 MS/ 3000 MS 运行内存限制 : 65536 KByte
总提交 : 2699 测试通过 : 1690

比赛描述

Calculate a + b.

输入

The input will consist of an integer N in the first line, and N pairs of integers a and b,separated by a space, one pair of integers per line.

输出

For each pair of input integers a and b you should output the sum of a and b in one line,and with one line of output for each line in input.

样例输入

2
1 5
3 3

样例输出

6
6

题目来源

/*    468ms#include<iostream>using namespace std;int main(){int N,a,b;cin>>N;while(N--){cin>>a>>b;cout<<a+b<<endl;}}*//*下面的程序只要46ms#include<stdio.h>int main(){int N,a,b;scanf("%d",&N);while(N--){scanf("%d%d",&a,&b);printf("%d\n",a+b);}}*//*下面的程序119ms#include<iostream>int main(){int N,a,b;scanf("%d",&N);while(N--){scanf("%d%d",&a,&b);std::cout<<a+b<<std::endl;}}*///下面的程序114ms#include<iostream>using namespace std;int main(){int N,a,b;scanf("%d",&N);while(N--){scanf("%d%d",&a,&b);cout<<a+b<<endl;}}//所以用scanf 和 printf 快

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