2015 Multi-University Training Contest-5 MZL's chemistry
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2015 Multi-University Training
Contest-5
MZL's chemistry
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)
Total Submission(s): 536 Accepted Submission(s): 389
Problem Description
MZL define F(X) as the first ionization energy of the chemical element X
Now he get two chemical elements U,V,given as their atomic number,he wants to compare F(U) and F(V)
It is guaranteed that atomic numbers belongs to the given set:{1,2,3,4,..18,35,36,53,54,85,86}
It is guaranteed the two atomic numbers is either in the same period or in the same group
It is guaranteed that x≠y
Input
There are several test cases
For each test case,there are two numbers u,v,means the atomic numbers of the two element
Output
For each test case,if F(u)>F(v),print "FIRST BIGGER",else print"SECOND BIGGER"
Sample Input
1 25 3
Sample Output
SECOND BIGGERFIRST BIGGER
Source
2015 Multi-University Training Contest 5
分析:
题目大意:给出两化学元素的序号(<=86),判断两者的第一电离能大小关系。
题目出的不是太好,题中并有没给出任何解决问题所需的信息,若不是化学专业或者有深厚化学基础的人不找资料想必做不出来。只能去网上查找元素第一电离能的规律,既然横竖都要百度,何不一次到位打表水过......
<pre name="code" class="cpp">#include<iostream>using namespace std;int main(){ double a[] = {0, 1312.0, 2372.3, 520.2, 899.5, 800.6, 1086.5, 1402.3, 1313.9, 1681.0, 2080.7, 495.8, 737.7, 577.5, 786.5, 1011.8, 999.6, 1251.2, 1520.6, 418.8, 589.8, 633.1, 658.8, 650.9, 652.9, 717.3, 762.5, 760.4, 737.1, 745.5, 906.4, 578.8, 762, 947.0, 941.0, 1139.9, 1350.8, 403.0, 549.5, 600, 640.1, 652.1, 684.3, 702, 710.2, 719.7, 804.4, 731.0, 867.8, 558.3, 708.6, 834, 869.3, 1008.4, 1170.4, 375.7, 502.9, 538.1, 534.4, 527, 533.1, 540, 544.5, 547.1, 593.4, 565.8, 573.0, 581.0, 589.3, 596.7, 603.4, 523.5, 658.5, 761, 770, 760, 840, 880, 870, 890.1, 1007.1, 589.4, 715.6, 703, 812.1, 890, 1037 }; int x, y; while (scanf("%d %d", &x, &y) != EOF) { if (a[x] > a[y]) cout << "FIRST BIGGER" << endl; else cout << "SECOND BIGGER" << endl; } return 0;}
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