HUD 2051 Bitset

Bitset

Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 16057    Accepted Submission(s): 12199

Problem Description

Give you a number on base ten,you should output it on base two.(0 < n < 1000)

 

Input

For each case there is a postive number n on base ten, end of file.

 

Output

For each case output a number on base two.

 

Sample Input

123

 

Sample Output

11011题意：十进制转二进制
#include <stdio.h>int main(){int n;int a[15],i;while(~scanf("%d",&n)){for(i=0;n;i++){a[i]=n%2;n/=2;}for(i=i-1;i>=0;i--)printf("%d",a[i]);putchar('\n');}return 0;}