Codeforces 492D Vanya and Computer Game
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题目链接:http://codeforces.com/problemset/problem/492/D
题意:游戏里,有2个玩家,a玩家1s内攻击x次,b玩家1s内攻击y次,给出若干个怪物的血量,问谁补得刀
思路:a玩家第i次攻击,b玩家第j次攻击,i/x > j/y(化简为i*y >j*x),i+j次是b的,若相等则i+j次攻击和i+j+1次攻击都视为同时攻击
#include <iostream>#include <cstdio>#include <cstring>#include <algorithm>#define maxn 2000300#define LL long longusing namespace std;int at[maxn];int main(){ int n,x,y; while (scanf("%d%d%d",&n,&x,&y)!=EOF) { LL cnt=1,xx=1,yy=1; memset(at,0,sizeof(at)); while (cnt<=x+y) { if (xx*y>yy*x) { at[cnt++]=2; yy++; } else if (xx*y<yy*x) { at[cnt++]=1; xx++; } else { at[cnt++]=3; at[cnt++]=3; xx++; yy++; } } at[0]=at[cnt-1]; LL hp; for (int i=0;i<n;i++) { scanf("%I64d",&hp); hp=hp%(x+y); if (at[hp]==3) printf("Both\n"); else if (at[hp]==1) printf("Vanya\n"); else printf("Vova\n"); } }}
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