Codeforces 492D Vanya and Computer Game 循环节找规律
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题目链接:点击打开链接
题意:
给定n只怪物的血量,x', y
第一个人每秒钟攻击x次,第二个人每秒钟攻击y次
每次攻击给所有存活的怪物造成一点伤害。
问每只怪物最后一击是谁打死的
思路:xy的最小公倍数内有个循环节,先跑出这个循环节(同时攻击时造成2点伤害,就在循环节里加2次both)
然后对于每只怪只要关心在循环节里坐落在哪个攻击点就好了
#include<bits/stdc++.h>using namespace std;const int maxn=2000010;int v[maxn];int main(){ long long n,x,y; cin>>n>>x>>y; int sum=0; for(int i=1,j=1;i<=y&&j<=x;) { if(i*x<j*y) {v[++sum]=2;i++;continue;} if(i*x>j*y) {v[++sum]=1;j++;continue;} if(i*x==j*y) {v[++sum]=0;v[++sum]=0;i++;j++;continue;} } long long m=x*y; for(int i=0;i<n;i++) { long long a; cin>>a; a=a%sum; if(v[a]==1) {cout<<"Vanya"<<endl;continue;} if(v[a]==2) {cout<<"Vova"<<endl;continue;} if(v[a]==0) {cout<<"Both"<<endl;continue;} } return 0;}
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