opencv3寻找最小包围矩形-minAreaRect函数

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#include<iostream>#include<vector>#include<opencv2/opencv.hpp>using namespace cv;using namespace std;int main(){Mat srcImage(Size(600, 600), CV_8UC3, Scalar(0));RNG &rng = theRNG();char key;while (1){//随机生成一些点//首先就是随机生成点的总数量int g_nPointCount = rng.uniform(3, 200);//接下来就是随机生成一些点的坐标vector<Point> points;for (int i = 0; i < g_nPointCount; i++){Point midPoint;midPoint.x = rng.uniform(srcImage.cols / 4, srcImage.cols * 3 / 4);midPoint.y = rng.uniform(srcImage.rows / 4, srcImage.rows * 3 / 4);points.push_back(midPoint);}//显示刚刚随机生成的那些点for (int i = 0; i < g_nPointCount; i++){circle(srcImage, points[i], 0, Scalar(rng.uniform(0, 255), rng.uniform(0, 255), rng.uniform(0, 255)), 3);}//在生成的那些随机点中寻找最小包围矩形//rectPoint变量中得到了矩形的四个顶点坐标RotatedRect rectPoint = minAreaRect(points);//定义一个存储以上四个点的坐标的变量Point2f fourPoint2f[4];//将rectPoint变量中存储的坐标值放到 fourPoint的数组中rectPoint.points(fourPoint2f);//根据得到的四个点的坐标  绘制矩形for (int i = 0; i < 3; i++){line(srcImage, fourPoint2f[i], fourPoint2f[i + 1], Scalar(rng.uniform(0, 255), rng.uniform(0, 255), rng.uniform(0, 255)), 3);}line(srcImage, fourPoint2f[0], fourPoint2f[3], Scalar(rng.uniform(0, 255), rng.uniform(0, 255), rng.uniform(0, 255)), 3);imshow("【绘制结束后的图像】", srcImage);key = waitKey();if (key == 27)break;elsesrcImage = Scalar::all(0);}return 0;}
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