Minimum Path Sum

题目：Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right which minimizes the sum of all numbers along its path.

Note: You can only move either down or right at any point in time.

思路：动态规划

核心思路是dp[i][j]=min{dp[i-1][j]+dp[i][j-1]}+table[i][j].

当前位置的最小和等于左边和右边位置最小和两者的小者+本方格数值。

代码：

class Solution {public://https://leetcode.com/problems/minimum-path-sum/    int minPathSum(vector<vector<int> >& grid) {        int m=grid.size(),n=grid[0].size();        if(m==0||n==0){            return 0;        }//        int sum[m][n];        for(int j=1;j<n;j++){            grid[0][j]=grid[0][j-1]+grid[0][j];        }        for(int i=1;i<m;i++){            grid[i][0]=grid[i-1][0]+grid[i][0];        }        for(int i=1;i<m;i++){            for(int j=1;j<n;j++){                grid[i][j]=min(grid[i-1][j],grid[i][j-1])+grid[i][j];            }        }        return grid[m-1][n-1];    }};