全排列POJ1256Anagram

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Time Limit: 1000MS Memory Limit: 10000K
Total Submissions: 18690 Accepted: 7602
Description
You are to write a program that has to generate all possible words from a given set of letters.
Example: Given the word “abc”, your program should - by exploring all different combination of the three letters - output the words “abc”, “acb”, “bac”, “bca”, “cab” and “cba”.
In the word taken from the input file, some letters may appear more than once. For a given word, your program should not produce the same word more than once, and the words should be output in alphabetically ascending order.
Input
The input consists of several words. The first line contains a number giving the number of words to follow. Each following line contains one word. A word consists of uppercase or lowercase letters from A to Z. Uppercase and lowercase letters are to be considered different. The length of each word is less than 13.
Output
For each word in the input, the output should contain all different words that can be generated with the letters of the given word. The words generated from the same input word should be output in alphabetically ascending order. An upper case letter goes before the corresponding lower case letter.
Sample Input
3
aAb
abc
acba
Sample Output
Aab
Aba
aAb
abA
bAa
baA
abc
acb
bac
bca
cab
cba
aabc
aacb
abac
abca
acab
acba
baac
baca
bcaa
caab
caba
cbaa
Hint
An upper case letter goes before the corresponding lower case letter.
So the right order of letters is ‘A’<’a’<’B’<’b’<…<’Z’<’z’.
Source
Southwestern European Regional Contest 1995

本题是全排列，难点是将字母与相应的数字关联，并通过字母快速获取对应的数字: A=1,B=3,C=5,D=7……a=2,b=4,c=6,d=8……

 #include <iostream>#include <cstring>#include<cstdio>#include <algorithm>using namespace std;int rank[300];bool cmp(char a, char b){    return rank[a]<rank[b];}int main(){     freopen("input.txt","r",stdin);    freopen("output.txt","w",stdout);    int t,i,len;    char str[20];    for (i=0; i<=26; i++){        rank[i+'A'] = i*2;        rank[i+'a'] = i*2+1;    }    scanf("%d", &t);    while(t--){        scanf("%s", str);        len = strlen(str);        sort(str, str+len, cmp);        do        {            printf("%s\n", str);        }while(next_permutation(str, str+len, cmp));    }    return 0;}