[LeetCode]154 有序数组旋转后的最小值 II

Find Minimum in Rotated Sorted Array II(找到有序数组旋转后的最小值 II)

【难度：Medium】
Follow up for “Find Minimum in Rotated Sorted Array”:
What if duplicates are allowed?

Would this affect the run-time complexity? How and why?
Suppose a sorted array is rotated at some pivot unknown to you beforehand.

(i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2).

Find the minimum element.

The array may contain duplicates.
153题的扩展，在原题基础上允许数组中出现重复数字。

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解题思路

使用二分查找时，在153题的基础上增加中间值和末端值相等的情况时的处理。同样使用常规查找时不需改变。

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c++代码如下：

//二分查找class Solution {public:    int findMin(vector<int>& nums) {        int low = 0;        int high = nums.size()-1;        while (low < high) {            int mid = (low+high)/2;            if (nums[mid] > nums[high])                low = mid+1;            else if (nums[mid] < nums[high])                high = mid;            else                high--;        }        return nums[high];    }};

//常规查找class Solution {public:    int findMin(vector<int>& nums) {        int min = INT_MAX;        for (int i = 0; i < nums.size(); i++)            if (min > nums[i])                min = nums[i];        return min;    }};