山东省第一届ACM省赛 D SDUT 2154 Shopping

Shopping

Time Limit: 1000ms   Memory limit: 65536K  有疑问？点这里^_^

题目描述

Saya and Kudo go shopping together.
You can assume the street as a straight line, while the shops are some points on the line.
They park their car at the leftmost shop, visit all the shops from left to right, and go back to their car.
Your task is to calculate the length of their route.

输入

The input consists of several test cases.
The first line of input in each test case contains one integer N (0<N<100001), represents the number of shops.
The next line contains N integers, describing the situation of the shops. You can assume that the situations of the shops are non-negative integer and smaller than 2^30.
The last case is followed by a line containing one zero.

输出

 For each test case, print the length of their shopping route.

示例输入

424 13 89 3767 30 41 14 39 420

示例输出

15270

#include <bits/stdc++.h>using namespace std;int main(){    int n,m;    while(~scanf("%d",&n) && n)    {        int MAX = -1;        int MIN = 0x3f3f3f3f;        for(int i=0; i<n; i++)        {            scanf("%d",&m);            MAX = max(MAX, m);            MIN = min(MIN, m);        }        printf("%d\n",(MAX-MIN)*2);    }}