gps数据转换为在百度地图下的坐标

来源：互联网发布：13个顶级域名服务器编辑：程序博客网时间：2024/04/30 07:08

通过GPS得到的经纬度数据，如果不加处理直接链接百度地图API的话，会出现偏差的问题，解决这个偏差可以将GPS数据处理成百度地图的坐标，转换过程是先将GPS数据转换为GOOGLE地图坐标，然后再将google地图坐标转换为百度地图坐标，具体代码如下

#include <iostream>#include <cmath>using namespace std;const double pi = 3.14159265358979324;const double a = 6378245.0;const double ee = 0.00669342162296594323;const double x_pi = 3.14159265358979324 * 3000.0 / 180.0;struct Loc{double Lon;//坐标的经度double Lat;//坐标的纬度};double transformLat(double x,double y);//将GPS坐标转换为google纬度坐标辅助函数double transformLon(double x,double y);//将GPS坐标转换为google经度坐标辅助函数Loc bd_encrypt(Loc gg);//将谷歌坐标转换为百度坐标Loc transform(Loc gps);//将GPS坐标转换为google地图int main(){Loc demo,gg,bd;demo.Lat = 22.502412986242;demo.Lon = 113.93832783228;gg = transform(demo);cout<<gg.Lat<<"     "<<gg.Lon<<endl;bd = bd_encrypt(gg);cout<<bd.Lat<<"     "<<bd.Lon<<endl;return 0;}double transformLat(double x,double y){double ret = -100.0 + 2.0 * x + 3.0 * y + 0.2 * y * y + 0.1 * x * y + 0.2 *sqrt(abs(x));    ret += (20.0 * sin(6.0 * x * pi) + 20.0 * sin(2.0 * x * pi)) * 2.0 / 3.0;    ret += (20.0 * sin(y * pi) + 40.0 * sin(y / 3.0 * pi)) * 2.0 / 3.0;    ret += (160.0 * sin(y / 12.0 * pi) + 320 * sin(y * pi / 30.0)) * 2.0 / 3.0;    return ret;}double transformLon(double x,double y){double ret = 300.0 + x + 2.0 * y + 0.1 * x * x + 0.1 * x * y + 0.1 * sqrt(abs(x));    ret += (20.0 * sin(6.0 * x * pi) + 20.0 * sin(2.0 * x * pi)) * 2.0 / 3.0;    ret += (20.0 * sin(x * pi) + 40.0 * sin(x / 3.0 * pi)) * 2.0 / 3.0;    ret += (150.0 * sin(x / 12.0 * pi) + 300.0 * sin(x / 30.0 * pi)) * 2.0 / 3.0;    return ret;}Loc bd_encrypt(Loc gg)//将谷歌坐标转换为百度坐标{Loc bd;    double x = gg.Lon, y = gg.Lat;double z = sqrt(x * x + y * y) + 0.00002 * sin(y * x_pi);double theta = atan2(y, x) + 0.000003 * cos(x * x_pi);bd.Lon = z * cos(theta) + 0.0065;bd.Lat = z * sin(theta) + 0.006;return bd;}Loc transform(Loc gps){Loc gg;    double dLat = transformLat(gps.Lon - 105.0, gps.Lat - 35.0);    double dLon = transformLon(gps.Lon - 105.0, gps.Lat - 35.0);    double radLat = gps.Lat / 180.0 * pi;    double magic = sin(radLat);    magic = 1 - ee * magic * magic;    double sqrtMagic = sqrt(magic);    dLat = (dLat * 180.0) / ((a * (1 - ee)) / (magic * sqrtMagic) * pi);    dLon = (dLon * 180.0) / (a / sqrtMagic * cos(radLat) * pi);    gg.Lat = gps.Lat + dLat;    gg.Lon = gps.Lon + dLon;return gg;}

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