hangman猜字游戏

hangman猜字游戏

记得去年公选haskell函数程序设计的时候老师让我们用haskell 语言实现过这个游戏,当时对于语言学得吃力,所以没有实现好,现在看到这个游戏的实现,觉得些许熟悉……

运用了string库函数,包括size(), length(), find(), constructor, operator== and so on.

// hangman 猜字游戏// created by yun on 2016, 05, 04#include<iostream>#include<cstring>#include<cstdlib>#include<ctime>#include<cctype>using namespace std;const int NUM = 26;const string wordlist[NUM] = {  "apiary", "beetle", "cereal", "danger", "ensign",  "florid", "garage", "health", "insult", "jackal",  "keeper", "loaner", "manage", "nonce", "onset",  "plaid", "quilt", "remote", "stolid", "strain",  "useful", "valid", "whence", "xenon", "yearn",  "zippy"};int main() {  // 随机数  srand(time(0));  char play;  cout << "will you play a word game?<y/n>";  cin >> play;  play = tolower(play);  while (play == 'y') {    string target = wordlist[rand()%NUM];    int length = target.length();    string attempt(length, '-');    string badchars;    int guesses = 6;    cout << "Guess my secret word. It has " << length << "letters, and you" <<    " guess one letter at a time. You get " << guesses << "wrong guesses" << endl;    cout << "your word: " << attempt << endl;    while (guesses > 0&&attempt != target) {      char letter;      cout << "guess a letter:";      cin >> letter;      if (badchars.find(letter) != string::npos||attempt.find(letter) != string::npos) {        cout << "You already guess that. Try again." << endl;        continue;      }      int loc = target.find(letter);      if (loc == string::npos) {        cout << "Oh, bad guess!" << endl;        --guesses;        badchars += letter;      } else {        cout << "Good guess!" << endl;        attempt[loc] = letter;        loc = target.find(letter, loc+1);        while (loc != string::npos) {          attempt[loc] = letter;          loc = target.find(letter, loc + 1);        }      }      cout << "Your word:" << attempt << endl;      if (attempt != target) {        if (badchars.length() > 0)          cout << "Bad choices: " << badchars << endl;        cout << guesses << " guesses left" << endl;      }    }    if (guesses > 0) cout << "That is rigth" << endl;    else cout << "Sorry, the word is " << target << endl;      cout << "Will you play another?<y/n>";      cin >> play;      play = tolower(play);  }  cout << "bye" << endl;  return 0;}

测试样例:

will you play a word game?<y/n>yGuess my secret word. It has 6letters, and you guess one letter at a time. You get 6wrong guessesyour word: ------guess a letter:eGood guess!Your word:----e-6 guesses leftguess a letter:aGood guess!Your word:--a-e-6 guesses leftguess a letter:tOh, bad guess!Your word:--a-e-Bad choices: t5 guesses leftguess a letter:rGood guess!Your word:--a-erBad choices: t5 guesses leftguess a letter:yOh, bad guess!Your word:--a-erBad choices: ty4 guesses leftguess a letter:iOh, bad guess!Your word:--a-erBad choices: tyi3 guesses leftguess a letter:pOh, bad guess!Your word:--a-erBad choices: tyip2 guesses leftguess a letter:mOh, bad guess!Your word:--a-erBad choices: tyipm1 guesses leftguess a letter:gOh, bad guess!Your word:--a-erBad choices: tyipmg0 guesses leftSorry, the word is loaner

注:npos变量是string类的静态变量,它的值是string对象所能存储的最大字符数,由于索引从0开始,所以它比最大的索引值大1,因此可以使用它来表示没有查找到字符或者字符串

if (badchars.find(letter) != string::npos||attempt.find(letter) != string::npos)

srand(time(0)); // 先设置种子
rand(); // 产生随机数