acm_Humble Numbers
来源:互联网 发布:java根据ip获取mac 编辑:程序博客网 时间:2024/05/19 15:25
题目:
1234111213212223100100058420
The 1st humble number is 1.The 2nd humble number is 2.The 3rd humble number is 3.The 4th humble number is 4.The 11th humble number is 12.The 12th humble number is 14.The 13th humble number is 15.The 21st humble number is 28.The 22nd humble number is 30.The 23rd humble number is 32.The 100th humble number is 450.The 1000th humble number is 385875.The 5842nd humble number is 2000000000.
思路:可以先用一个vector容器把这5842个数求出来。。然每输入一个数取就可以了。。
代码:
#include <iostream>
#include <string>
#include<stdio.h>
#include<vector>
#include<cmath>
using namespace std;
int inline min(int a,int b)
{
return a<b?a:b;
}
int main(){
int n = 5842, m;
char s[4][3]={"th","st","nd","rd"};
vector<int> v;
int a = 0, b = 0, c = 0, d = 0;
v.push_back(1);
while(--n){
int r2 = v[a] * 2;
int r3 = v[b] * 3;
int r5 = v[c] * 5;
int r7 = v[d] * 7;
m = min(r2, r3);
m = min(m, r5);
m = min(m, r7);
v.push_back(m);
if(r2 == m)
a+=1;
if(r3 == m)
b+=1;
if(r5 == m)
c+=1;
if(r7 == m)
d+=1;
}
while(cin>>n&&n!=0)
{
string cc=(n % 10 < 4 && n % 100 != 11 && n % 100 != 12 && n % 100 != 13)?s[n % 10]:"th";
cout<<"The "<<n<<cc<<" humble number is "<<v[n - 1]<<"."<<endl;
}
return 0;
}
- acm_Humble Numbers
- Numbers
- Numbers
- Numbers
- Numbers
- Numbers
- Ugly Numbers
- Humble Numbers
- Humble Numbers
- Palindrom Numbers
- Niven Numbers
- Alien Numbers
- Alien Numbers
- Phone Numbers
- usaco_humble numbers
- Alien Numbers
- Alien Numbers
- hdu1058humble numbers
- Middle-题目96:187. Repeated DNA Sequences
- 【刷题之路】判断平衡二叉树
- leetcode 217. Contains Duplicate
- lucene 文档评分 及 CustomScoreQuery
- 贪心法——最优装载问题
- acm_Humble Numbers
- 刚毕业的时候遇到的一些问题,可能很简单但是也可以看一看
- 工资类(改)
- Middle-题目97:148. Sort List
- C++ limits头文件的用法(numeric_limits)
- HTML5标莶使用初级技巧
- java-对象管理-集合
- Middle-题目98:316. Remove Duplicate Letters
- hibernate如何使用hql语句查询时间区间段