HDU 1847 Good Luck in CET-4 Everybody!(博弈)
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思路:手推了一下1到10的情况,发现是3的倍数的时候必败,其他情况必胜
#include<bits/stdc++.h>using namespace std;int main(){int n;while(scanf("%d",&n)!=EOF){if(n%3==0)cout << "Cici" << endl;elsecout << "Kiki"<<endl;}}
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