258. Add Digits--LeetCode Record
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Given a non-negative integer num, repeatedly add all its digits until the result has only one digit.
For example:
Given num = 38, the process is like: 3 + 8 = 11, 1 + 1 = 2. Since 2 has only one digit, return it.
Follow up:
Could you do it without any loop/recursion in O(1) runtime?
class Solution { func addDigits(num: Int) -> Int { if num < 10 { return num } return num % 9 == 0 ? 9 : num % 9 }} 0 0
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