Leetcode Add Digits
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Given a non-negative integer num, repeatedly add all its digits until the result has only one digit.
For example:
Given num = 38, the process is like: 3 + 8 = 11, 1 + 1 = 2. Since 2 has only one digit, return it.
Difficulty: Easy
public class Solution { public int addDigits(int num) { if(num <= 9) return num; int ans = 0; while(num != 0){ ans += num%10; num = num/10; } return addDigits(ans); }} 0 0
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