LeetCode 118. Pascal's Triangle
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Given numRows, generate the first numRows of Pascal's triangle.
For example, given numRows = 5,
Return
[ [1], [1,1], [1,2,1], [1,3,3,1], [1,4,6,4,1]]
Pascal三角的规则是:每一个数等于头上左右两个数之和。
class Solution {public: vector<vector<int>> generate(int numRows) { vector<int> v; vector<vector<int>> res; if(numRows == 0) return res; v.push_back(1); res.push_back(v); if(numRows == 1) return res; v.push_back(1); res.push_back(v); if(numRows == 2) return res; v.clear(); int i; for(i = 3; i <= numRows; i ++){ v.push_back(1); int j; for(j = 1; j < i - 1; j ++){ v.push_back(res[i - 2][j - 1] + res[i - 2][j]); } v.push_back(1); res.push_back(v); v.clear(); } return res; }};
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