HDU 3549 网络流初步

Flow ProblemTime Limit: 5000/5000 MS (Java/Others)    Memory Limit: 65535/32768 K (Java/Others)Total Submission(s): 12912    Accepted Submission(s): 6154Problem DescriptionNetwork flow is a well-known difficult problem for ACMers. Given a graph, your task is to find out the maximum flow for the weighted directed graph.InputThe first line of input contains an integer T, denoting the number of test cases.For each test case, the first line contains two integers N and M, denoting the number of vertexes and edges in the graph. (2 <= N <= 15, 0 <= M <= 1000)Next M lines, each line contains three integers X, Y and C, there is an edge from X to Y and the capacity of it is C. (1 <= X, Y <= N, 1 <= C <= 1000)OutputFor each test cases, you should output the maximum flow from source 1 to sink N.Sample Input23 21 2 12 3 13 31 2 12 3 11 3 1Sample OutputCase 1: 1Case 2: 2

昨天看了一个下午的网络流，大体上懂了 Ford - Fulkerson 方法的EK算法，拿这题贯通一下

#include <cstdio>#include <cstring>#include <queue>#include <climits>using namespace std;#define MAX_V 15*2#define MAX_E 1000*2int Pre[MAX_E]; bool Visit[MAX_E];int Map[MAX_E][MAX_E];      bool BFS(int s,int t,int V,int E){    int cur;    queue<int> Q;    memset(Pre,0,sizeof Pre);    memset(Visit,false,sizeof Visit);    Visit[s] = true;   Q.push(s);       while(!Q.empty())    {        cur = Q.front();Q.pop();        if(cur == t) return true;          for(int i=1;i<=V;++i)        {            if(!Visit[i] && Map[cur][i])             {                Q.push(i);                Pre[i] = cur;                Visit[i] = true;            }        }    }    return false;}int Max_flow(int s,int t,int V,int E)  {    int flow = 0;    while(true)    {        if(!BFS(s,t,V,E)) return flow;          int Min = INT_MAX;        for(int i=t;i!=s;i=Pre[i])             Min = min(Min,Map[Pre[i]][i]);        for(int i=t;i!=s;i=Pre[i])        {            Map[Pre[i]][i] -= Min;              Map[i][Pre[i]] += Min;          }        flow += Min;    }}void Handle(int V,int E){    memset(Map,0,sizeof Map);    for(int i = 1,u,v,c;i <= E;i++)     {        scanf("%d %d %d",&u,&v,&c);        Map[u][v] += c;                  }}int main(void){  // freopen("F:\\test.txt","r",stdin);    int T;scanf("%d",&T);    for(int i=1;i<=T;i++)    {        int V,E;        scanf("%d %d",&V,&E);   //V<=15,E<=1000,C<=1000        Handle(V,E);        printf("Case %d: %d\n",i,Max_flow(1,V,V,E));    }}