Balance--DP
来源:互联网 发布:收银会员软件 编辑:程序博客网 时间:2024/06/09 16:37
Balance
Time Limit: 1000MS Memory Limit: 30000KTotal Submissions: 13527 Accepted: 8476
Description
Gigel has a strange "balance" and he wants to poise it. Actually, the device is different from any other ordinary balance.
It orders two arms of negligible weight and each arm's length is 15. Some hooks are attached to these arms and Gigel wants to hang up some weights from his collection of G weights (1 <= G <= 20) knowing that these weights have distinct values in the range 1..25. Gigel may droop any weight of any hook but he is forced to use all the weights.
Finally, Gigel managed to balance the device using the experience he gained at the National Olympiad in Informatics. Now he would like to know in how many ways the device can be balanced.
Knowing the repartition of the hooks and the set of the weights write a program that calculates the number of possibilities to balance the device.
It is guaranteed that will exist at least one solution for each test case at the evaluation.
It orders two arms of negligible weight and each arm's length is 15. Some hooks are attached to these arms and Gigel wants to hang up some weights from his collection of G weights (1 <= G <= 20) knowing that these weights have distinct values in the range 1..25. Gigel may droop any weight of any hook but he is forced to use all the weights.
Finally, Gigel managed to balance the device using the experience he gained at the National Olympiad in Informatics. Now he would like to know in how many ways the device can be balanced.
Knowing the repartition of the hooks and the set of the weights write a program that calculates the number of possibilities to balance the device.
It is guaranteed that will exist at least one solution for each test case at the evaluation.
Input
The input has the following structure:
• the first line contains the number C (2 <= C <= 20) and the number G (2 <= G <= 20);
• the next line contains C integer numbers (these numbers are also distinct and sorted in ascending order) in the range -15..15 representing the repartition of the hooks; each number represents the position relative to the center of the balance on the X axis (when no weights are attached the device is balanced and lined up to the X axis; the absolute value of the distances represents the distance between the hook and the balance center and the sign of the numbers determines the arm of the balance to which the hook is attached: '-' for the left arm and '+' for the right arm);
• on the next line there are G natural, distinct and sorted in ascending order numbers in the range 1..25 representing the weights' values.
• the first line contains the number C (2 <= C <= 20) and the number G (2 <= G <= 20);
• the next line contains C integer numbers (these numbers are also distinct and sorted in ascending order) in the range -15..15 representing the repartition of the hooks; each number represents the position relative to the center of the balance on the X axis (when no weights are attached the device is balanced and lined up to the X axis; the absolute value of the distances represents the distance between the hook and the balance center and the sign of the numbers determines the arm of the balance to which the hook is attached: '-' for the left arm and '+' for the right arm);
• on the next line there are G natural, distinct and sorted in ascending order numbers in the range 1..25 representing the weights' values.
Output
The output contains the number M representing the number of possibilities to poise the balance.
Sample Input
2 4-2 3 3 4 5 8
Sample Output
2题目链接:http://poj.org/problem?id=1837
哎,看了好久,还是去搜了题解。。。
http://blog.csdn.net/libin56842/article/details/21116143
http://blog.csdn.net/lyhvoyage/article/details/45064083
http://blog.csdn.net/kindlucy/article/details/5796065
啥也不说了,说多了都是泪啊。。。。QAQ
代码:
#include <cstdio>#include <cstring>#include <iostream>using namespace std;int a[300000];int b[300000];int dp[30][30000];int main(){ int n,m; int i,j,k; while(~scanf("%d%d",&n,&m)) { memset(a,0,sizeof(a)); memset(b,0,sizeof(b)); for(i=1;i<=n;i++) scanf("%d",&a[i]); for(i=1;i<=m;i++) { scanf("%d",&b[i]); } memset(dp,0,sizeof(dp)); dp[0][7500]=1; for(i=1;i<=m;i++) { for(j=0;j<=15000;j++) { if(dp[i-1][j]) { for(k=1;k<=n;k++) { dp[i][j+a[k]*b[i]]+=dp[i-1][j]; } } } } printf("%d\n",dp[m][7500]); } return 0;}
0 0
- Balance--DP
- pku 1837 Balance(DP)
- POJ 1837 Balance DP
- POJ--1837--Balance--DP
- POJ 1837 Balance (DP)
- POJ 1837 Balance DP
- POJ 1837 Balance (DP)
- poj 1837 Balance (DP)
- POJ 1837 Balance DP
- POJ 1837 Balance (DP)
- POJ 1837 Balance (DP)
- poj 1837 Balance -DP
- POJ 1837 Balance(DP)
- POJ-1837-Balance-DP
- hdoj5616Jam's balance【dp】
- POJ1837 Balance(DP)
- poj-1837 Balance【dp】
- Poj 1837 Balance【DP】
- 线性表
- MySQL操作表的约束
- HDU 1010 Tempter of the Bone DFS+奇偶剪枝
- HTML5规范中的MessageEvent以及SSE
- Windows下DLL文件调试
- Balance--DP
- STM32F103C8开发GPIO操作(一)
- Excutor
- namespace的用法
- 从网络中获取图片或动图(gif)
- Effective C++_Item21读书笔记
- 平衡树之treap
- c++调用gnuplot显示数据图
- POJ 2774Long Long Message