Matrix

Description

There is a matrix  that has  rows and  columns .Then we perform operations: 

1 x y: Swap row x and row y ; 

2 x y: Swap column x and column y ; 

3 x y: Add y to all elements in row x ; 

4 x y: Add y to all elements in column x ;

Input

There are multiple test cases. The first line of input contains an integer  indicating the number of test cases. For each test case: 

The first line contains three integers ,  and . 
The following  lines describe the matrix M. for all . 
The following  lines contains three integers ,  and . 

Output

For each test case, output the matrix  after all  operations.

Sample Input

23 4 21 2 3 42 3 4 53 4 5 61 1 23 1 102 2 21 1010 11 1 22 1 2

Sample Output

12 13 14 151 2 3 43 4 5 61 1010 1

 

题目很容易看懂：有4种操作，

1：交换a行和b行的数，

2：交换a列和b列的数，

3；给a行每个数都加上b,

4:给a列每个数都加上b;
思路：可以给每行和每列都增加一个数组，方便去交换每行每列的数，还要在增加radd[],cadd[]数组，去记录哪一行哪一列各增加了多少:

#include<cstdio>#include<cstring>#include<algorithm>using namespace std;int row[1009],col[1009],map[1009][1009];int radd[1009],cadd[1009];int main(){int t,n,m,k,q,x1,x2,y1,y2,i,j,op;int a,b;scanf("%d",&t);while(t--){memset(radd,0,sizeof(radd));memset(cadd,0,sizeof(cadd));scanf("%d%d%d",&n,&m,&q);for(i=1;i<=n;i++){for(j=1;j<=m;j++)scanf("%d",&map[i][j]);}for(i=1;i<=n;i++)row[i]=i;for(i=1;i<=m;i++)col[i]=i;for(i=0;i<q;i++){scanf("%d%d%d",&op,&a,&b);if(op==1)swap(row[a],row[b]);else if(op==2)swap(col[a],col[b]);else if(op==3)radd[row[a]]+=b;else if(op==4)cadd[col[a]]+=b;}for(i=1;i<=n;i++){for(j=1;j<=m;j++){if(j>1) printf(" ");printf("%d",map[row[i]][col[j]]+radd[row[i]]+cadd[col[j]]);}printf("\n");}}return 0;}