Product of Array Except Self

Given an array of n integers where n > 1, nums, return an array output such that output[i] is equal to the product of all the elements of nums except nums[i].

Solve it without division and in O(n).

For example, given [1,2,3,4], return [24,12,8,6].

Follow up:
Could you solve it with constant space complexity? (Note: The output array does not count as extra space for the purpose of space complexity analysis.)

public class Solution {public static void main(String[] args) {// TODO Auto-generated method stubint[] nums = {1,0,3,4};int[] res = Solution.productExceptSelf(nums);for(int x : res)System.out.print(x+" ");}    public static int[] productExceptSelf(int[] nums) {    int numsLen = nums.length;    int[] res = new int[numsLen];    res[0] = 1;    for(int i = 1 ;i < numsLen ;i++)//先从左向右乘，每一位对前几位数进行累乘保存到res中    {    res[i] = res[i-1]*nums[i-1];    }    int right = 1;    for(int i = numsLen-1;i>=0 ;i--)//从右向左，每一位对后几位进行累乘。    {    res[i] *= right;    right *= nums[i];    }    return res;    }}