[LeetCode]Climbing Stairs(Java)
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昨天怒刷n到链表题,感觉简单题没什么多余技巧,固没有总结
这道题非常常见,做了好多遍了已经,最简单的动态规划
一种斐波纳切数列变种题
<span style="font-size:24px;">public class Solution { public int climbStairs(int n) { if(n == 1) return 1; else if(n == 2) return 2; else{ int i = 3,first = 2,next = 3,m=0; while(i!=n){ i++; m=next; next = next+first; first = m; } return next; } }}</span>
2016/8/30
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