[Leetcode] Add Digits

Given a non-negative integer num, repeatedly add all its digits until the result has only one digit.

For example:

Given num = 38, the process is like: 3 + 8 = 11, 1 + 1 = 2. Since 2 has only one digit, return it.

Follow up:

Could you do it without any loop/recursion in O(1) runtime?

public class Solution {    public int addDigits(int num) {        if(num<10) return num;        int sum=0;        while(num>0)        {            sum+=num%10;            num=num/10;        }        return addDigits(sum);    }}