lua关于表的处理和输出方式整理

来源：互联网发布：snmp数据采集编辑：程序博客网时间：2024/05/21 10:35

题目在文件里面，注意对表中元素操作时，不要改变原表元素。

若对t表元素操作

另取表t2=t，对t2中元素赋值，print（t）时 t中相应位置的值也改变了。

local x=0

local g = {}

for i,v in ipairs(t) do

table.insert(g,v);

end

采用此方法对t2表定义。

--直接用t2=t1，对t2做改变时t1中元素也会改变。

--一个不确定数据数目的表，0可以代表一个范围内的任意数，求输出的是不是等差数列

function istableorder(t,a,b)

local x=0

local g = {}

for i,v in ipairs(t) do

table.insert(g,v);

end

c={}

d={}

for i,v in pairs(t) do

if v~=0 then

x=x+1

table.insert(c,#c+1,i) --记录不是零的数的位置

table.insert(d,#d+1,v) --记录不是零的数的值

end

-- print(unpack(d))

-- print(unpack(c))

if x==0 then --全都为零

if(#t<=(b-a+1)) then

return true

elsereturn false

end

elseif x==1 then --有一个不是零

if c[1]==1 or c[1]==#t then

if ((d[1]+#t-1)>(b)) then

return false

elseif((d[1]-#t+1)<a) then

return false

end

return true

elseif(d[1]+(#t-c[1])<=b)and(d[1]-(c[1]-1)>=a) then --最大值小于零的范围

return true --最小值大于零的范围

elseif(d[1]-(#t-c[1])>=a)and(d[1]+(c[1]-1)<=b) then

return true

else

return false

end

else

local e

e=(d[2]-d[1])/(c[2]-c[1])

if c[1]==1 then

for i=1,#t-1 do

if g[i+1]~=g[i]+e then

if g[i+1]~=0 then

return false

else

g[i+1]=g[i]+e

if g[i+1]>b or g[i+1]<a then

return false

end

return true

elseif c[2]==#t then

for i=#t,2,-1 do

if g[i-1]~=g[i]-e then

if g[i-1]~=0 then

return false

else

g[i-1]=g[i]-e

if g[i-1]>b or g[i-1]<a then

return false

end

return true

-- else

-- for i=c[1],2,-1 do

-- if g[i-1]~=g[i]-e then

-- if g[i-1]~=0 then

-- return false

-- else

-- g[i-1]=g[i]-e

-- if g[i-1]>b or g[i-1]<a then

-- return false

-- end

-- for i=c[1],#t-1 do

-- if g[i+1]~=g[i]+e then

-- if g[i+1]~=0 then

-- return false

-- else

-- g[i+1]=g[i]+e

-- if g[i+1]>b or g[i+1]<a then

-- return false

-- end

-- return true --]]

end

-- a=6

-- b=7

-- t={5,0,0}

-- r={0,1,0,0,0,9}

-- s={0,0,0,0,5,0,0}

-- u={0,0,0,1,0,0,0,}

-- v={0,0,1,0,3}

-- w={0,0,3,0,1}

-- x={-1,0,0,1,0,3}

-- y={-1,0,1,2,0,0,5}

-- z={-2,0,0,0,0,0,0,}

-- sr={0,0,0,4,0,0,0,0,-1}

-- function shuchu( t )

-- print(unpack(t))

-- end

-- print(shuchu(t),istableorder(t,a,b))

-- print(shuchu(r),istableorder(r,a,b))

-- print(shuchu(s),istableorder(s,a,b))

-- print(shuchu(u),istableorder(u,a,b))

-- print(shuchu(v),istableorder(v,a,b))

-- print(shuchu(w),istableorder(w,a,b))

-- print(shuchu(x),istableorder(x,a,b))

-- print(shuchu(y),istableorder(y,a,b))

-- print(shuchu(z),istableorder(z,a,b))

-- print(shuchu(sr),istableorder(sr,a,b))

slot={

{1,2,3,4,5,6,7,8,0,0,0,0,0,0,0,0},

{1,2,3,4,5,6,7,7},

{-3,-1,1,3,5},

{-3,-1,1,3,4},

{1,0,2,5},

{1,0,3,4},

{0,0,0,1,3,5},

{0,0,1,2,0,4,5},

{0,0,1,2,0,0,4},

{0,0,1,2,0,0,5},

{0,0,0,1,0,0,0},

{0,0,0,0,0},

{1,5,6},

{1,5,9},

{5,4,3,2,1},

{2,0,0},

{0,0,0,0,0},

{1,0,0,0,0},

{0,0,0,0,1},

{0,0,1,0,0},

{0,1,0,3,0},

{1,2,0,0,0},

{0,0,0,1,2},

{1,2,3,4,5},

{2,4,6,8,10},

{3,5,7,0,11},

{-9,-7,0,0,-1},

{-9,0,0,0,-1},

{0,-7,-5,0,-1},

{0,0,0,-3,0},

{-9,0,0,0,0},

{0,0,0,0,-1},

{-9,0,-5,0,-1},

{0,-9,-7,0,0},

}

a=-1

b=3

for i=1,table.getn(slot) do

temp = slot[i];

if(istableorder(temp,a,b)) then

--print("ture|"..table.concat(temp,",").."}".." is order");

print("true".." "..table.concat(temp,',').." a="..a.." b="..b)

else

--print("false|"..table.concat(temp,",").."}".." is not order");

print("false".." "..table.concat(temp,',').." a="..a.." b="..b)

end

test={0,0,0,1,2}

istableorder(test,a,b)

print(unpack(test))

0 0