android快速实现毛玻璃效果
来源:互联网 发布:java语言程序设计下载 编辑:程序博客网 时间:2024/04/29 21:07
为了实现毛玻璃效果,本文采用的是
StackBlur
模糊算法,这种算法应用非常广泛,能得到非常良好的毛玻璃效果。在这里,我们使用的是它的Java实现代码FastBlur.java。不过直接使用这种算法很容易造成内存溢出,对此,我们应该对原图进行缩放package com.example.user.baozoumanhua.text;import android.graphics.Bitmap;/** * Created by user on 2016/9/11. */publicclass FastBlurUtil { publicstatic Bitmap doBlur(Bitmap sentBitmap, int radius, boolean canReuseInBitmap){ Bitmap bitmap; if (canReuseInBitmap) { bitmap = sentBitmap; } else { bitmap = sentBitmap.copy(sentBitmap.getConfig(), true); } if (radius < 1) { return (null); } int w = bitmap.getWidth(); int h = bitmap.getHeight(); int[] pix = newint[w * h]; bitmap.getPixels(pix, 0, w, 0, 0, w, h); int wm = w - 1; int hm = h - 1; int wh = w * h; int div = radius + radius + 1; int r[] = newint[wh]; int g[] = newint[wh]; int b[] = newint[wh]; int rsum, gsum, bsum, x, y, i, p, yp, yi, yw; int vmin[] = newint[Math.max(w, h)]; int divsum = (div + 1) >> 1; divsum *= divsum; int dv[] = newint[256 * divsum]; for (i = 0; i < 256 * divsum; i++) { dv[i] = (i / divsum); } yw = yi = 0; int[][] stack = newint[div][3]; int stackpointer; int stackstart; int[] sir; int rbs; int r1 = radius + 1; int routsum, goutsum, boutsum; int rinsum, ginsum, binsum; for (y = 0; y < h; y++) { rinsum = ginsum = binsum = routsum = goutsum = boutsum = rsum = gsum = bsum = 0; for (i = -radius; i <= radius; i++) { p = pix[yi + Math.min(wm, Math.max(i, 0))]; sir = stack[i + radius]; sir[0] = (p & 0xff0000) >> 16; sir[1] = (p & 0x00ff00) >> 8; sir[2] = (p & 0x0000ff); rbs = r1 - Math.abs(i); rsum += sir[0] * rbs; gsum += sir[1] * rbs; bsum += sir[2] * rbs; if (i > 0) { rinsum += sir[0]; ginsum += sir[1]; binsum += sir[2]; } else { routsum += sir[0]; goutsum += sir[1]; boutsum += sir[2]; } } stackpointer = radius; for (x = 0; x < w; x++) { r[yi] = dv[rsum]; g[yi] = dv[gsum]; b[yi] = dv[bsum]; rsum -= routsum; gsum -= goutsum; bsum -= boutsum; stackstart = stackpointer - radius + div; sir = stack[stackstart % div]; routsum -= sir[0]; goutsum -= sir[1]; boutsum -= sir[2]; if (y == 0) { vmin[x] = Math.min(x + radius + 1, wm); } p = pix[yw + vmin[x]]; sir[0] = (p & 0xff0000) >> 16; sir[1] = (p & 0x00ff00) >> 8; sir[2] = (p & 0x0000ff); rinsum += sir[0]; ginsum += sir[1]; binsum += sir[2]; rsum += rinsum; gsum += ginsum; bsum += binsum; stackpointer = (stackpointer + 1) % div; sir = stack[(stackpointer) % div]; routsum += sir[0]; goutsum += sir[1]; boutsum += sir[2]; rinsum -= sir[0]; ginsum -= sir[1]; binsum -= sir[2]; yi++; } yw += w; } for (x = 0; x < w; x++) { rinsum = ginsum = binsum = routsum = goutsum = boutsum = rsum = gsum = bsum = 0; yp = -radius * w; for (i = -radius; i <= radius; i++) { yi = Math.max(0, yp) + x; sir = stack[i + radius]; sir[0] = r[yi]; sir[1] = g[yi]; sir[2] = b[yi]; rbs = r1 - Math.abs(i); rsum += r[yi] * rbs; gsum += g[yi] * rbs; bsum += b[yi] * rbs; if (i > 0) { rinsum += sir[0]; ginsum += sir[1]; binsum += sir[2]; } else { routsum += sir[0]; goutsum += sir[1]; boutsum += sir[2]; } if (i < hm) { yp += w; } } yi = x; stackpointer = radius; for (y = 0; y < h; y++) { // Preserve alpha channel: ( 0xff000000 & pix[yi] ) pix[yi] = (0xff000000 & pix[yi]) | (dv[rsum] << 16) | (dv[gsum] << 8) | dv[bsum]; rsum -= routsum; gsum -= goutsum; bsum -= boutsum; stackstart = stackpointer - radius + div; sir = stack[stackstart % div]; routsum -= sir[0]; goutsum -= sir[1]; boutsum -= sir[2]; if (x == 0) { vmin[y] = Math.min(y + r1, hm) * w; } p = x + vmin[y]; sir[0] = r[p]; sir[1] = g[p]; sir[2] = b[p]; rinsum += sir[0]; ginsum += sir[1]; binsum += sir[2]; rsum += rinsum; gsum += ginsum; bsum += binsum; stackpointer = (stackpointer + 1) % div; sir = stack[stackpointer]; routsum += sir[0]; goutsum += sir[1]; boutsum += sir[2]; rinsum -= sir[0]; ginsum -= sir[1]; binsum -= sir[2]; yi += w; } } bitmap.setPixels(pix, 0, w, 0, 0, w, h); return (bitmap); }}
int scaleRatio = 10; int blurRadius = 8;Bitmap scaledBitmap = Bitmap.createScaledBitmap(bitmap,bitmap.getWidth() / scaleRatio, bitmap.getHeight() / scaleRatio, false);
可以看出使用该方法很简单,第一个参数就是原图,第二个和第三个就是缩放后的尺寸,第四个参数true表示返回边缘光滑的图片,反之则得到锯齿边缘的图片,Bitmap my = FastBlurUtil.doBlur(scaledBitmap, 10, false);//10b表示的就是模糊效果,值 越大越模糊 iv.setImageBitmap(my);
这样就快速实现了毛玻璃效果 1 0
- android快速实现毛玻璃效果
- android快速实现毛玻璃效果
- Android快速实现毛玻璃效果
- Android快速毛玻璃虚化效果实现
- Android毛玻璃效果实现
- Android实现毛玻璃效果
- Android毛玻璃效果实现
- Android毛玻璃效果的实现(本文系转载一种快速毛玻璃虚化效果实现)
- Android一种快速毛玻璃虚化效果实现
- 一种快速毛玻璃虚化效果实现--Android
- Android 实现快速高斯模糊(毛玻璃)效果算法
- android实现的毛玻璃效果
- Android 毛玻璃效果的实现
- Android 毛玻璃效果实现(Glide)
- Android毛玻璃效果简单实现
- 一种快速毛玻璃虚化效果实现
- 一种快速毛玻璃虚化效果实现
- 快速毛玻璃虚化效果实现
- LeetCode学习篇十一——Range Sum Query - Immutable
- MySQL——数据库语言+语法
- HPC —— 高性能计算
- 119. Pascal's Triangle II (python)
- node.js利用javascript中构造函数继承,实现模块调用
- android快速实现毛玻璃效果
- 121. Best Time to Buy and Sell Stock (python)
- 书本ISBN号码校验
- 省市联动(struts2+ajax+非数据库)
- c++模版-学习记录
- ios JSPatch热更新技术详解
- 二分查找
- 10.30 E - 汉诺塔III
- B哥传