【LeetCode】 172. Factorial Trailing Zeroes
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Given an integer n, return the number of trailing zeroes in n!.
Note: Your solution should be in logarithmic time complexity.
public class Solution { public int trailingZeroes(int n) { if (n == 0) { return 0; } return n / 5 + trailingZeroes(n / 5); }} 0 0
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