leetcode81. Search in Rotated Sorted Array II
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81. Search in Rotated Sorted Array II
Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand.
(i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2).
Write a function to determine if a given target is in the array.
The array may contain duplicates.
解法
因为最坏情况下是O(n),相当于一个for循环,而且有重复的元素不能判断是在数组左半部分还是右半部分。
public class Solution { public boolean search(int[] nums, int target) { if (nums == null || nums.length == 0) { return false; } for (int i = 0; i < nums.length; i++) { if (nums[i] == target) { return true; } } return false; }}
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