遍历列表，找出具体元素的索引

问：从列表中找出所有数字2的索引号：

name = ['d', 'a', 'b', 'c', 'd', 2, 'b', 'c', '2', 2, 'b', 'a', 2, 2, 'a', 'hello', 'world', 2, 'peng']

first_position = 0for i in range(name.count(2)):    next_position = name[first_position:].index(2)    print 'the index is: ', next_position + first_position    first_position += next_position + 1