C++简单练习题2——求回文数

#include <iostream>using namespace std;bool Palindrome(int x);int main() {for (int i = 11; i <= 999; i++){if (Palindrome(i) && Palindrome(i * i) && Palindrome(i * i * i))cout << i << endl;}    return 0;}bool Palindrome(int x){int n = x;int a = 0;while (n > 0){a = a * 10 + n % 10;  //颠倒比较n = n / 10;}return a == x;}