LeetCode——1. Two Sum
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Given an array of integers, return indices of the two numbers such that they add up to a specific target.
You may assume that each input would have exactly one solution, and you may not use the same element twice.
Example:
Given nums = [2, 7, 11, 15], target = 9,Because nums[0] + nums[1] = 2 + 7 = 9,return [0, 1].
/** * Note: The returned array must be malloced, assume caller calls free(). */int* twoSum(int* nums, int numsSize, int target) { int *ans = (int*)malloc(sizeof(int)*2); int i ; for( i = 0 ; i < numsSize ; i++) { int j ; for( j =i+1 ; j< numsSize ; j++) { if(nums[i] + nums[j] == target) { *ans = i ;*(ans+1) = j ; break;}}}return ans;} 0 0
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