ruby 解决 php aes 与 ruby aes zero 算法不用的问题

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gemfile 加如下代码

gem"ruby-mcrypt"

使用

require 'mcrypt'module Crypt  def self.append_features(base)    super    base.extend(AesBase64)  end  module AesBase64    # require 'openssl'    # require 'base64'    # require 'hex_string'    KEY = 'xyz' #you key

    IV = "123" # you iv    def encrypt(data)      crypto = Mcrypt.new(:rijndael_128, :cbc, KEY, IV, :zeros)      enc = crypto.encrypt(escape(data))      # use for latter      # aes = OpenSSL::Cipher::AES128.new('CBC')      # aes.padding = 0      # aes.encrypt      # aes.key = KEY      # aes.iv = IV      # enc = aes.update(data) << aes.final      Base64.strict_encode64(enc)    end    def decrypt(data)      base64 = Base64.strict_decode64(data)      crypto = Mcrypt.new(:rijndael_128, :cbc, KEY, IV, :zeros)      crypto.decrypt(base64)      # use for latter      # dec = Base64.strict_decode64(data)      # aes = OpenSSL::Cipher::AES128.new('CBC').decrypt      # aes.padding = 0      # aes.key = KEY      # aes.iv = IV      # aes.update(dec) << aes.final    end    def escape(string)      if string.respond_to?(:force_encoding)        string = string.encode(::Encoding::UTF_8, :undef => :replace).force_encoding(::Encoding::BINARY)      end      json = string.          # gsub(escape_regex) { |s| ESCAPED_CHARS[s] }.          gsub(/([\xC0-\xDF][\x80-\xBF]|             [\xE0-\xEF][\x80-\xBF]{2}|             [\xF0-\xF7][\x80-\xBF]{3})+/nx) { |s|        s.unpack("U*").pack("n*").unpack("H*")[0].gsub(/.{4}/n, '\\\\u\&')      }      json = %(#{json})      json.force_encoding(::Encoding::UTF_8) if json.respond_to?(:force_encoding)      json    end  endend

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