pat 1065. A+B and C (64bit)

原题链接：https://www.patest.cn/contests/pat-a-practise/1065

          1065. A+B and C (64bit) (20)

时间限制

100 ms

内存限制

65536 kB

代码长度限制

16000 B

判题程序

Standard

作者

HOU, Qiming

Given three integers A, B and C in [-2⁶³, 2⁶³], you are supposed to tell whether A+B > C.

Input Specification:

The first line of the input gives the positive number of test cases, T (<=10). Then T test cases follow, each consists of a single line containing three integers A, B and C, separated by single spaces.

Output Specification:

For each test case, output in one line "Case #X: true" if A+B>C, or "Case #X: false" otherwise, where X is the case number (starting from 1).

Sample Input:

31 2 32 3 49223372036854775807 -9223372036854775808 0

Sample Output:

Case #1: falseCase #2: trueCase #3: false

主要对于溢出情况做特殊判断

// pat_A+B and C (64bit).cpp : 定义控制台应用程序的入口点。//#include <cstdio>#include <cstring>#include <cstdlib>#include <cmath>typedef long long ll;ll a, b, c, res;int main(int argc, char* argv[]){int T,cas=1;scanf("%d", &T);while (T--){int flag=1;scanf("%lld%lld%lld", &a, &b, &c);res = a + b;if (a < 0 && b < 0 && res>=0)//注意res==0也要包括flag = 0;else if (a>0 && b > 0 && res <=0)//写成res< =0就错？？flag = 1;else if (res > c)flag = 1;elseflag = 0;printf("Case #%d: %s\n", cas++, flag == 1 ? "true" : "false");}return 0;}