Hdu 2602 Bone Collector

Bone Collector

Problem Description
Many years ago , in Teddy’s hometown there was a man who was called “Bone Collector”. This man like to collect varies of bones , such as dog’s , cow’s , also he went to the grave …
The bone collector had a big bag with a volume of V ,and along his trip of collecting there are a lot of bones , obviously , different bone has different value and different volume, now given the each bone’s value along his trip , can you calculate out the maximum of the total value the bone collector can get ?

Input
The first line contain a integer T , the number of cases.
Followed by T cases , each case three lines , the first line contain two integer N , V, (N <= 1000 , V <= 1000 )representing the number of bones and the volume of his bag. And the second line contain N integers representing the value of each bone. The third line contain N integers representing the volume of each bone.

Output
One integer per line representing the maximum of the total value (this number will be less than 231).

Sample Input
1
5 10
1 2 3 4 5
5 4 3 2 1

Sample Output
14

01背包水题

#include<bits/stdc++.h>using namespace std;int main(){    ios::sync_with_stdio(0);    cin.tie(0);    int T;    cin>>T;    while(T--) {        int N,V;        cin>>N>>V;        vector<long long>value(1005,0),weight(1005,0),dp(1005,0);        for(int i=1;i<=N;i++)        cin>>value[i];        for(int i=1;i<=N;i++)        cin>>weight[i];        for(int i=1;i<=N;i++)            for(int j=V;j>=weight[i];j--)            dp[j]=max(dp[j],dp[j-weight[i]]+value[i]);        cout<<dp[V]<<endl;    }    return 0;}