C++11多线程原子类型

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C++11中10个线程同时竞争资源，会出现竞争问题

处理方式1，mutex

#include<iostream>#include<vector>#include<thread>#include<functional>#include <time.h>#include<atomic> #include<mutex>using namespace std;mutex mut;void func(int &counter){       mut.lock();for(int i=0;i<100001;++i)  ++counter;mut.unlock();}int main(){clock_t start = clock();int counter=0;    vector<thread> threads;for(int i=0;i<10;++i){threads.push_back(thread{func,ref(counter)});}for(auto &t:threads){t.join();}clock_t finish = clock();cout<<"Result = "<<counter<<endl;cout<<"duration:"<<finish -start<<"ms"<<endl;return 0; }

处理方式2：原子操作

#include<iostream>#include<vector>#include<thread>#include<functional>#include <time.h>#include<atomic> #include<mutex>using namespace std;//mutex mut;void func(atomic<int> &counter){       //mut.lock();for(int i=0;i<100001;++i)  ++counter;   //mut.unlock();}int main(){clock_t start = clock();atomic<int> counter(0);    vector<thread> threads;for(int i=0;i<10;++i){threads.push_back(thread{func,ref(counter)});}for(auto &t:threads){t.join();}clock_t finish = clock();cout<<"Result = "<<counter<<endl;cout<<"duration:"<<finish -start<<"ms"<<endl;return 0; }

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