连续序列相加得N问题

// test48.cpp : Defines the entry point for the console application.//#include "stdafx.h"#include <iostream>using namespace std;void get_num(int n){int sum=0;for(int current=0;current<(n/2+2);current++){int begin=current;sum=0;for(;sum<n;begin++)sum+=begin;if(sum==n)for(int i=current;i<begin;i++)printf("%d ",i);printf("/n");}}int main(int argc, char* argv[]){get_num(9);}