输入n，输出对应的所有长度为n的二进制串

#include <iostream>#include <stack>#include <math.h>using namespace std;void print(int n){int max = (int)pow((double)2,(double)n);unsigned int mask = 0x00000001;int i,j;stack<int> stack1;for(i=0;i<max;i++){for(j=0;j<n;j++){stack1.push(i&mask?1:0);mask<<=1;}while(stack1.size()){cout<<stack1.top();stack1.pop();}cout<<endl;mask>>=n;}}int main(){cout<<"请输入长度n:";int n;cin>>n;cout<<"所有长度为n的二进制串为:"<<endl;print(n);return 0;}