ZOJ 3741 Eternal Reality

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题意:要参加一个比赛,要想赢一场比赛,自身等级必须大于等于对手的等级,初始等级为L,比赛场数N.主人公可以吃药,吃了药之后等级临时变成L + 1持续X场,X场之后会变成0级并且持续Y场后又变回初始等级L.求最多能赢多少场.

设dp[i][0]为在第i场吃药到最后最多能赢多少场,dp[i][1]为在第i场不吃药到最后最多能赢多少场.

1)dp[i][0] = [i, X + Y - 1]的赢得场数+max(dp[i + X + Y][0], dp[i + X + Y])

2)dp[i][1] = max([i, k]的赢得场数 + dp[k + 1][0]) i<=k<=N

从后往前推.

#include <cstdio>#include <algorithm>#include <memory.h>using namespace std;const int MAX = 105;int main(int argc, char const *argv[]){int dp[MAX][2];int level[MAX];int L, N, X, Y;while(scanf("%d%d%d%d", &L, &N, &X, &Y) == 4){memset(dp, 0, sizeof(dp));for(int i = 1; i <= N; ++i){scanf("%d", &level[i]);}for(int i = N; i >= 1; --i){//case 1: use the Level Upper before round idp[i][0] = 0;int wins = 0;for(int k = i; k < i + X && k <= N; ++k){if(L >= level[k] || (L < 5 && L + 1 >= level[k])){//can't use when at level 5 or greater++wins;}}for(int k = i + X; k < i + X + Y && k <= N; ++k){if(0 >= level[k]){++wins;}}dp[i][0] = wins + max(dp[min(i + X + Y, N + 1)][0], dp[min(i + X + Y, N + 1)][1]);//case 2: do not use the Level Upper before round idp[i][1] = 0;wins = 0;for(int k = i; k <= N; ++k){if(L >= level[k]){wins++;}dp[i][1] = max(dp[i][1], wins + max(dp[k + 1][0], dp[k + 1][1]));}}printf("%d\n", max(dp[1][0], dp[1][1]));}return 0;}

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