BNU 29375 Two Strings

字符串排序后逐个计算

#include<bits/stdc++.h>using namespace std;char s1[100020],s2[100020];int main(){    int T,m;    scanf("%d",&T);    for(int kase=1;kase<=T;kase++)    {        scanf("%d%s%s",&m,s1,s2);        sort(s1,s1+m);        sort(s2,s2+m);        int ans=0;        for(int i=0;i<m;i++)            ans+=abs(s1[i]-s2[i]);        printf("Case %d: %d\n",kase,ans);    }    return 0;}