【leetcode 字符串处理】Compare Version Numbers
来源:互联网 发布:电脑死机数据恢复 编辑:程序博客网 时间:2024/05/17 02:49
【leetcode 字符串处理】Compare Version Numbers
@author:wepon
@blog:http://blog.csdn.net/u012162613
1、题目
Compare two version numbers version1 and version1.
If version1 > version2 return 1, if version1 < version2 return -1, otherwise return 0.
You may assume that the version strings are non-empty and contain only digits and the .
character.
The .
character does not represent a decimal point and is used to separate number sequences.
For instance, 2.5
is not "two and a half" or "half way to version three", it is the fifth second-level revision of the second first-level revision.
Here is an example of version numbers ordering:
0.1 < 1.1 < 1.2 < 13.37
2、分析
题意:题意很清晰,就是比较“版本号”大小,给定的版本号version1和version2是字符串类型的,当version1>version2的时候,返回1,反之返回-1。
这道题属于细节处理题,除了字符串处理繁琐一点之外没有什么。
解题思路:先分别将version1、version2字符串按'.'分割成多个子串,每个子串转化成整型存入容器。最后再比较两个容器中对应位置的数的大小。当然需要考虑它们长度不同的情况。
注意点:
(1)version的形式:10.23.1、01.23、1.2.3.4....诸如此类
(2)字符串转化成整型,我的程序中直接用库函数stoi()
3、代码
class Solution {public: int compareVersion(string version1, string version2) { vector<int> result1=getInt(version1); vector<int> result2=getInt(version2); int len1=result1.size(); int len2=result2.size(); if(len2<len1) return -1*compareVersion(version2, version1); int i=0; while(i<len1 && result1[i]==result2[i]) i++; if(i==len1){ //str1和str2前len1位都相等,则看看str2后面的len2-len1位是否都为0即可判断它们的大小 int j=len2-1; while(j >= len1){ if(result2[j--]!=0) return -1; } return 0; }else{ //str1和str2前len1位不都相等,直接判断第i位 if(result1[i]<result2[i]) return -1; else return 1; } }private://将version字符串按'.'拆成多个,转化为整型放入容器 vector<int> getInt(string version){ vector<int> result; int len=version.size(); int pre=0; for(int i=0;i<len;i++){ if(version[i]=='.'){ string str(version.begin()+pre,version.begin()+i); //注意这种初始化形式,左闭右开,即str不包括version[version.begin()+i] result.push_back(stoi(str)); pre=i+1; } }string str(version.begin()+pre,version.end()); result.push_back(stoi(str)); return result; }};
2 0
- 【leetcode 字符串处理】Compare Version Numbers
- Leetcode Compare Version Numbers
- [leetcode] Compare Version Numbers
- [leetcode] Compare Version Numbers
- Leetcode: Compare Version Numbers
- 【Leetcode】:Compare Version Numbers
- leetcode:Compare Version Numbers
- [LeetCode]Compare Version Numbers
- [leetCode] Compare Version Numbers
- [leetcode] Compare Version Numbers
- 【Leetcode】Compare Version Numbers
- [LeetCode] Compare Version Numbers
- Leetcode: Compare Version Numbers
- LeetCode-Compare Version Numbers
- leetcode:Compare Version Numbers
- LeetCode--Compare Version Numbers
- Compare Version Numbers Leetcode
- Compare Version Numbers --- LeetCode
- eclipse中开启两个控制台查看两个程序的输出
- Qt中使用中文字符编译报错的问题
- 1.QT中的容器QVector,QList,QSet,QMap,QQueue,QStack,QMultiMap,QSingleList等
- NGUI 3.5教程(八)Scroll Bar 滚动条-制作聊天框
- 无类型数据排序实现
- 【leetcode 字符串处理】Compare Version Numbers
- jQuery对象的动画处理
- Unity网格合并_材质合并(待续)
- linux编程-文件操作(4)
- 调和级数
- 【Cocos2d-x】可以显示在线图片的CCSprite
- 素数的筛选找法
- xcode开发入门印象
- Intellij Idea快捷键(mac版)