[leetcode 172] Factorial Trailing Zeroes
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Given an integer n, return the number of trailing zeroes in n!.
Note: Your solution should be in logarithmic time complexity.
class Solution {public: int trailingZeroes(int n) { int power = 1; int c = 0; int f = (int) (n/(pow(5, power))); while(f > 0){ c += f; f = (int) (n/(pow(5, ++power))); } return c; }}; 0 0
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