Leetcode: Minimum path sum

来源:互联网 发布:win10 64位下载 知乎 编辑:程序博客网 时间:2024/05/24 13:28

又是一题动态规划,我获得的是到所有点的最小值,代码如下:


class Solution {public:    int minPathSum(vector<vector<int> > &grid) {        int min[1000][1000] = {0};        if(grid.size()<=0) return 0;        int m = grid.size();        int n = grid[0].size();        for(int i = 0;i < m;i++){            for(int j = 0;j < n;j++){                if(i==0&&j==0) min[i][j] = grid[i][j];                else if(i==0) min[i][j] = min[i][j-1]+grid[i][j];                else if(j==0) min[i][j] = min[i-1][j]+grid[i][j];                else                    min[i][j] = (min[i][j-1]<min[i-1][j]?min[i][j-1]:min[i-1][j])+grid[i][j];            }        }        return min[m-1][n-1];    }};

0 0
原创粉丝点击