ZOJ.1951 Goldbach's Conjecture【素数】 2015/09/22

Goldbach's Conjecture

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Time Limit: 2 Seconds      Memory Limit: 65536 KB

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In 1742, Christian Goldbach, a German amateur mathematician, sent a letter to Leonhard Euler in which he made the following conjecture:

Every even number greater than 4 can be

written as the sum of two odd prime numbers.

For example:

8 = 3 + 5. Both 3 and 5 are odd prime numbers.
20 = 3 + 17 = 7 + 13.
42 = 5 + 37 = 11 + 31 = 13 + 29 = 19 + 23.

Today it is still unproven whether the conjecture is right. (Oh wait, I have the proof of course, but it is too long to write it on the margin of this page.)

Anyway, your task is now to verify Goldbach's conjecture for all even numbers less than a million.

Input

The input will contain one or more test cases.

Each test case consists of one even integer n with 6 <= n < 1000000.

Input will be terminated by a value of 0 for n.

Output

For each test case, print one line of the form n = a + b, where a and b are odd primes. Numbers and operators should be separated by exactly one blank like in the sample output below. If there is more than one pair of odd primes adding up to n, choose the pair where the difference b - a is maximized. If there is no such pair, print a line saying "Goldbach's conjecture is wrong."

Sample Input

8
20
42
0

Sample Output

8 = 3 + 5
20 = 3 + 17
42 = 5 + 37

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Source: University of Ulm Local Contest 1998

将一个数分解成两个素数相加，若有多解，则输出两解差值最大的一组

#include<iostream>#include<cstdio>#include<cstring>#include<cmath>using namespace std;bool prime[1000010];void init(){    memset(prime,false,sizeof(prime));    for( int i = 2 ; i <= 1000000 ; ++i ){        if( !prime[i] ){            for( int j = i+i ; j <= 1000000 ; j+=i )                prime[j] = true;        }    }}int main(){    init();    int n;    while( cin>>n ){        if( !n ) break;        for( int i = 2 ; i <= n/2 ; ++i ){            if( !prime[i] && !prime[n-i] ){                printf("%d = %d + %d\n",n,i,n-i);                break;            }        }    }    return 0;}