hdu 5492(矩阵模型的变形)

来源:互联网 发布:博泰与创业软件 编辑:程序博客网 时间:2024/05/22 03:47

参考博客:http://blog.csdn.net/u014679804/article/details/48769267




#include<iostream>#include<cstdio>#include<cstring>using namespace std;const int maxn = 35;const int inf = 0x3f3f3f3f;int n,m,map[maxn][maxn];int dp[maxn][maxn][1800];int main(){int t,cas = 1;scanf("%d",&t);while(t--){scanf("%d%d",&n,&m);for(int i = 1; i <= n; i++)for(int j = 1; j <= m; j++)scanf("%d",&map[i][j]);memset(dp,inf,sizeof(dp));dp[1][1][map[1][1]] = map[1][1] * map[1][1];for(int i = 1; i <= n; i++)for(int j = 1; j <= m; j++)for(int k = 0; k <= 1800; k++){if(dp[i][j][k] == inf) continue;if(i + 1 <= n)dp[i+1][j][k+map[i+1][j]] = min(dp[i+1][j][k+map[i+1][j]],dp[i][j][k] + map[i+1][j]*map[i+1][j]);if(j + 1 <= m)dp[i][j+1][k+map[i][j+1]] = min(dp[i][j+1][k+map[i][j+1]],dp[i][j][k] + map[i][j+1]*map[i][j+1]);}int ans = inf;for(int i = 0; i <= 1800; i++)if(dp[n][m][i] != inf)ans = min(ans,(n+m-1)*dp[n][m][i] - i*i);printf("Case #%d: %d\n",cas++,ans);}return 0;}



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