poj_2996 Help Me with the Game（模拟）

Help Me with the Game

Time Limit: 1000MS Memory Limit: 65536KTotal Submissions: 4481 Accepted: 2826

Description

Your task is to read a picture of a chessboard position and print it in the chess notation.

Input

The input consists of an ASCII-art picture of a chessboard with chess pieces on positions described by the input. The pieces of the white player are shown in upper-case letters, while the black player's pieces are lower-case letters. The letters are one of "K" (King), "Q" (Queen), "R" (Rook), "B" (Bishop), "N" (Knight), or "P" (Pawn). The chessboard outline is made of plus ("+"), minus ("-"), and pipe ("|") characters. The black fields are filled with colons (":"), white fields with dots (".").

Output

The output consists of two lines. The first line consists of the string "White: ", followed by the description of positions of the pieces of the white player. The second line consists of the string "Black: ", followed by the description of positions of the pieces of the black player.

The description of the position of the pieces is a comma-separated list of terms describing the pieces of the appropriate player. The description of a piece consists of a single upper-case letter that denotes the type of the piece (except for pawns, for that this identifier is omitted). This letter is immediatelly followed by the position of the piece in the standard chess notation -- a lower-case letter between "a" and "h" that determines the column ("a" is the leftmost column in the input) and a single digit between 1 and 8 that determines the row (8 is the first row in the input).

The pieces in the description must appear in the following order: King("K"), Queens ("Q"), Rooks ("R"), Bishops ("B"), Knights ("N"), and pawns. Note that the numbers of pieces may differ from the initial position because of capturing the pieces and the promotions of pawns. In case two pieces of the same type appear in the input, the piece with the smaller row number must be described before the other one if the pieces are white, and the one with the larger row number must be described first if the pieces are black. If two pieces of the same type appear in the same row, the one with the smaller column letter must appear first.

Sample Input

+---+---+---+---+---+---+---+---+|.r.|:::|.b.|:q:|.k.|:::|.n.|:r:|+---+---+---+---+---+---+---+---+|:p:|.p.|:p:|.p.|:p:|.p.|:::|.p.|+---+---+---+---+---+---+---+---+|...|:::|.n.|:::|...|:::|...|:p:|+---+---+---+---+---+---+---+---+|:::|...|:::|...|:::|...|:::|...|+---+---+---+---+---+---+---+---+|...|:::|...|:::|.P.|:::|...|:::|+---+---+---+---+---+---+---+---+|:P:|...|:::|...|:::|...|:::|...|+---+---+---+---+---+---+---+---+|.P.|:::|.P.|:P:|...|:P:|.P.|:P:|+---+---+---+---+---+---+---+---+|:R:|.N.|:B:|.Q.|:K:|.B.|:::|.R.|+---+---+---+---+---+---+---+---+

Sample Output

White: Ke1,Qd1,Ra1,Rh1,Bc1,Bf1,Nb1,a2,c2,d2,f2,g2,h2,a3,e4Black: Ke8,Qd8,Ra8,Rh8,Bc8,Ng8,Nc6,a7,b7,c7,d7,e7,f7,h7,h6

理解题目的排序意思多花了点时间，以为是根据位置上方块的颜色去排，因为自以为这个条件没有用上。后来多试了几下数据才知道是自己想多了，

直接按棋子的颜色去排就好了。

#include <iostream>#include <cstdio>#include <cstdlib>#include <cstring>#include <cmath>#include <stack>#include <bitset>#include <queue>#include <set>#include <map>#include <string>#include <algorithm>#define FOP freopen("data.txt","r",stdin)#define inf 0x3f3f3f3f#define maxn 20#define mod 1000000007#define PI acos(-1.0)#define LL long longusing namespace std;int K = 10, Q = 9, R = 8, B = 7, N = 6, P = 5;struct Chess{    int x, y;    int kind;};bool compare(Chess a, Chess b){    if(a.kind != b.kind) return a.kind > b.kind;    else if(a.x != b.x) return a.x > b.x;    else return a.y < b.y;}bool compare2(Chess a, Chess b){    if(a.kind != b.kind) return a.kind > b.kind;    else if(a.x != b.x) return a.x < b.x;    else return a.y < b.y;}vector<Chess> vb, vw;int main(){    char s[20];    Chess chess;    for(int i = 1; i <= 17; i++)    {        scanf("%s", s + 1);        if(!(i & 1))        {            for(int j = 3; j <= 33; j += 4)            {                if(s[j] == ':' || s[j] == '.') continue;                chess.x = 8 - i / 2 + 1;                chess.y = (j + 1) / 4;                if(s[j] == 'K' || s[j] == 'k') chess.kind = K;                else if(s[j] == 'Q' || s[j] == 'q') chess.kind = Q;                else if(s[j] == 'R' || s[j] == 'r') chess.kind = R;                else if(s[j] == 'B' || s[j] == 'b') chess.kind = B;                else if(s[j] == 'N' || s[j] == 'n') chess.kind = N;                else if(s[j] == 'P' || s[j] == 'p') chess.kind = P;                if(s[j] >= 'A' && s[j] <= 'Z') vw.push_back(chess);                else vb.push_back(chess);            }        }    }    sort(vb.begin(), vb.end(), compare);    sort(vw.begin(), vw.end(), compare2);    vector<Chess>::iterator iter;    printf("White: ");    for(iter = vw.begin(); iter != vw.end(); iter++)    {        chess = *iter;        if(chess.kind == K) printf("K");        else if(chess.kind == Q) printf("Q");        else if(chess.kind == R) printf("R");        else if(chess.kind == B) printf("B");        else if(chess.kind == N) printf("N");        printf("%c%d", chess.y + 'a' - 1, chess.x);        if(iter + 1 != vw.end())printf(",");    }    printf("\n");    printf("Black: ");    for(iter = vb.begin(); iter != vb.end(); iter++)    {        chess = *iter;        if(chess.kind == K) printf("K");        else if(chess.kind == Q) printf("Q");        else if(chess.kind == R) printf("R");        else if(chess.kind == B) printf("B");        else if(chess.kind == N) printf("N");        printf("%c%d", chess.y + 'a' - 1, chess.x);        if(iter + 1 != vb.end())printf(",");    }    return 0;}