HDU ACM 11 2047 阿牛的EOF牛肉串

#include <iostream>using namespace std;int main(){int n;__int64 Lu[41];while (cin >> n){Lu[0] = 3;Lu[1] = 8;int s = 2, t = 1;for (int i = 2; i < n; i++)Lu[i] = 2 * (Lu[i - 1] + Lu[i - 2]);cout << Lu[n - 1] << endl;}return 0;}