PAT甲级C语言.1001. 害死人不偿命的(3n+1)猜想

#include <stdio.h>

int main(){  int judge(int b);  int a;  scanf("%d",&a);  for(int i=0;a!=1;++i)    a=judge(a);  printf("%d\n",i);

  return 0;}int judge(int b){  if(b%2==0)    b=b/2;  else    b=(3*b+1)/2;  return b;}