ccfcsp201612-四边形不等式优化

来源：互联网发布：sql insert语句返回值编辑：程序博客网时间：2024/05/16 18:43

四边形不等式优化学习地址：http://blog.csdn.net/u014800748/article/details/45750737
重点是：m(i,j)=min{m(i,k-1),m(k,j)}+w(i,j)(s(i,j-1)≤k≤s(i+1,j))（min也可以改为max）
知识点一样的题目：玲珑杯1066
参考链接：
http://blog.csdn.net/acmore_xiong/article/details/53745970
http://blog.csdn.net/acmore_xiong/article/details/53744680
http://yangff.logdown.com/posts/138211
http://blog.csdn.net/u014800748/article/details/45750737

#include <bits/stdc++.h>using namespace std;int n, m,  a[1005];int p[1005][1005], sum[1005];long long dp[1005][1005];int main(){    scanf("%d", &n);    for(int i = 1; i <= n; i++) scanf("%d", &a[i]);    memset(dp, 0x3f, sizeof(dp));    sum[0] = 0;    for(int i = 1; i <= n; i++)    {        dp[i][i] = 0;        p[i][i] = i;        sum[i] = sum[i - 1] + a[i];    }    for(int len = 2; len <= n; len++)    {        for(int i = 1; i + len - 1 <= n; i++)        {            int j = i + len - 1;            for(int k = p[i][j - 1]; k <= p[i + 1][j]; k++)            {                long long val = dp[i][k] + dp[k + 1][j] + (sum[j] - sum[i - 1]);                if(val < dp[i][j])                {                    dp[i][j]= val;                    p[i][j] = k;                }            }        }    }    printf("%lld\n", dp[1][n]);    return 0;}

0 0