【动态规划】zoj Course Selection System
来源:互联网 发布:百度网盘mac版本 编辑:程序博客网 时间:2024/06/14 08:27
There are n courses in the course selection system of Marjar University. The i-th course is described by two values: happiness Hi and credit Ci. If a student selects m courses x1, x2, ...,xm, then his comfort level of the semester can be defined as follows:
Edward, a student in Marjar University, wants to select some courses (also he can select no courses, then his comfort level is 0) to maximize his comfort level. Can you help him?
Input
There are multiple test cases. The first line of input contains an integer T, indicating the number of test cases. For each test case:
The first line contains a integer n (1 ≤ n ≤ 500) -- the number of cources.
Each of the next n lines contains two integers Hi and Ci (1 ≤ Hi ≤ 10000, 1 ≤ Ci ≤ 100).
It is guaranteed that the sum of all n does not exceed 5000.
We kindly remind you that this problem contains large I/O file, so it's recommended to use a faster I/O method. For example, you can use scanf/printf instead of cin/cout in C++.
Output
For each case, you should output one integer denoting the maximum comfort.
Sample Input
2310 15 12 1021 102 10
Sample Output
1910
Hint
For the first case, Edward should select the first and second courses.
For the second case, Edward should select no courses.
#include<cstdio>#include<cstring>#include<algorithm>#include<cstdlib>#include<queue>#include<cmath>#define mem(a,b) memset(a,b,sizeof(a))using namespace std;typedef long long ll;const int maxn=500105;ll dp[maxn],H[maxn],C[maxn];int main(){ int n; ll sum; int T; while(~scanf("%d",&T)) { while(T--) { mem(dp,0); mem(H,0); mem(C,0); sum=0; scanf("%d",&n); for(int i=0;i<n;i++) scanf("%lld%lld",&H[i],&C[i]); for(int i=0;i<n;i++) sum+=C[i]; for(int i=0;i<n;i++) { for(ll j=sum;j>=C[i];j--) dp[j]=max(dp[j],dp[j-C[i]]+H[i]); } ll ans=0; for(int i=1;i<=sum;i++) { if(dp[i]<0) continue; ll the=dp[i]*dp[i]-i*dp[i]-i*i; ans=max(ans,the); } printf("%lld\n",ans); } } return 0;}
- 【动态规划】zoj Course Selection System
- Course Selection System ZOJ
- ZOJ 3956 Course Selection System
- ZOJ 3956 Course Selection System
- zoj 3956 Course Selection System
- zoj 3956-Course Selection System(背包)
- ZOJ 3956 Course Selection System 01背包
- Zoj 3956 Course Selection System【01背包】
- ZOJ 3956 Course Selection System 01背包
- ZOJ 3956 Course Selection System (dp)
- ZOJ-3956 Course Selection System,01背包!
- ZOJ-3956 Course Selection System(01背包)
- 浙大17年校赛(ZOJ 3956)Course Selection System[01背包]
- ZOJ 3956 Course Selection System(01背包)
- Zoj 3956 Course Selection System (01背包)
- ZOJ 3956 Course Selection System 01背包变形
- ZOJ 3956 Course Selection System (dp 01背包)
- 浙大校赛 ZOJ 3956Course Selection System (01背包)
- L2-021. 点赞狂魔
- 如何使/etc/profile中修改的配置立刻生效?
- 【ESP8266】关于调试fatal exception/自动重启的一些经验分享
- The supplied data appears to be in the Office 2007+ XML
- linux下的僵尸进程及atexit函数的使用及验证
- 【动态规划】zoj Course Selection System
- 动态规划练习题-16(踩方格)
- 练习
- Camera2谷歌官方文档(1) 概述
- L3-013. 非常弹的球
- CentOS 7 编译安装Python2.6.1
- C#编写动态链接库类库dll文件
- Linux(十一) 之 负载均衡(下)
- TCP协议